-16x^2+48x+10=39

Solution for -16x^2+48x+10=39 equation:

-16x^2+48x+10=39

We move all terms to the left:

-16x^2+48x+10-(39)=0

We add all the numbers together, and all the variables

-16x^2+48x-29=0

a = -16; b = 48; c = -29;
Δ = b2-4ac
Δ = 482-4·(-16)·(-29)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-8\sqrt{7}}{2*-16}=\frac{-48-8\sqrt{7}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+8\sqrt{7}}{2*-16}=\frac{-48+8\sqrt{7}}{-32}
$